A wheelchair ramp at a Mumbai hospital rises 1m for every 5m distance along the ground. The angle of inclination is:
A wheelchair ramp at a Mumbai hospital rises 1m for every 5m distance along the ground. The angle of inclination is:
- A. tan⁻¹(1/5)
- B. sin⁻¹(1/5)
- C. cos⁻¹(1/5)
- D. cot⁻¹(1/5)
Answer: A) tan⁻¹(1/5)
Explanation: The rise (opposite) is 1m and run (adjacent) is 5m. tan(θ) = 1/5. Hence, θ = tan⁻¹(1/5).
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