imo class 12 inverse trigonometric functions

The value of sin⁻¹(3/5) + sin⁻¹(8/17) is:

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The value of sin⁻¹(3/5) + sin⁻¹(8/17) is:

  • A. sin⁻¹(77/85)
  • B. sin⁻¹(13/85)
  • C. sin⁻¹(84/85)
  • D. sin⁻¹(11/17)

Answer: A) sin⁻¹(77/85)

Explanation: Let A = sin⁻¹(3/5) and B = sin⁻¹(8/17). sin(A+B) = sinA cosB + cosA sinB = (3/5)(15/17) + (4/5)(8/17) = 45/85 + 32/85 = 77/85.

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