If cos⁻¹x + cos⁻¹y = 2π/3, then sin⁻¹x + sin⁻¹y equals:
If cos⁻¹x + cos⁻¹y = 2π/3, then sin⁻¹x + sin⁻¹y equals:
- A. π/3
- B. 2π/3
- C. π/6
- D. π/4
Answer: A) π/3
Explanation: We know sin⁻¹x + cos⁻¹x = π/2 for each x. Adding: (sin⁻¹x+cos⁻¹x)+(sin⁻¹y+cos⁻¹y) = π/2+π/2 = π. So sin⁻¹x+sin⁻¹y = π − (cos⁻¹x+cos⁻¹y) = π − 2π/3 = π/3.
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