The solution of sin⁻¹(1−x) − 2sin⁻¹(x) = π/2 is:

The solution of sin⁻¹(1−x) − 2sin⁻¹(x) = π/2 is:

• A. 0
• B. 1/2
• C. 1
• D. Both 0 and 1/2

Answer: A) 0

Explanation: Substitute x = 0: sin⁻¹(1) − 0 = π/2, which is true. If x = 1/2: sin⁻¹(1/2) − 2sin⁻¹(1/2) = π/6 − 2(π/6) = −π/6 ≠ π/2. Thus x=0 is the only solution.