The equation 2cos⁻¹x + sin⁻¹x = 11π/6 has: A. No solution B. One solution C. Two solutions D. Infinitely many solutions Answer: A) No solution Explanation: cos⁻¹x + (cos⁻¹x + sin⁻¹x) = cos⁻¹x + π/2 = 11π/6 → cos⁻¹x = 11π/6 − π/2 = 4π/3. But cos⁻¹x ∈ [0, π]. 4π/3 ∉ [0, π]. So no solution.

imo class 12 inverse trigonometric functions

The equation 2cos⁻¹x + sin⁻¹x = 11π/6 has:

VAVidaara Admin Asked 6d ago 0 views 0 answers

The equation 2cos⁻¹x + sin⁻¹x = 11π/6 has:

Answer: A) No solution

Explanation: cos⁻¹x + (cos⁻¹x + sin⁻¹x) = cos⁻¹x + π/2 = 11π/6 → cos⁻¹x = 11π/6 − π/2 = 4π/3. But cos⁻¹x ∈ [0, π]. 4π/3 ∉ [0, π]. So no solution.

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