If sin⁻¹(a) + sin⁻¹(b) + sin⁻¹(c) = 3π/2, then the value of a²⁰²⁶ + b²⁰²⁶ + c²⁰²⁶ is:
If sin⁻¹(a) + sin⁻¹(b) + sin⁻¹(c) = 3π/2, then the value of a²⁰²⁶ + b²⁰²⁶ + c²⁰²⁶ is:
- A. 0
- B. 1
- C. 2
- D. 3
Answer: D) 3
Explanation: Max value of sin⁻¹(x) is π/2. So a = b = c = 1. Therefore, 1²⁰²⁶ + 1²⁰²⁶ + 1²⁰²⁶ = 3.
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