The domain of f(x) = √(sin⁻¹x) is:

The domain of f(x) = √(sin⁻¹x) is:

• A. [0, 1]
• B. [−1, 1]
• C. [0, π/2]
• D. (0, 1)

Answer: A) [0, 1]

Explanation: √(sin⁻¹x) is defined when sin⁻¹x ≥ 0 and x ∈ [−1, 1]. sin⁻¹x ≥ 0 ⇒ x ≥ 0, and x ≤ 1, so the domain is [0, 1].