If sin⁻¹x + sin⁻¹y = 2π/3, then cos⁻¹x + cos⁻¹y equals:
If sin⁻¹x + sin⁻¹y = 2π/3, then cos⁻¹x + cos⁻¹y equals:
- A. π/3
- B. π/6
- C. 2π/3
- D. π/2
Answer: A) π/3
Explanation: sin⁻¹x+cos⁻¹x = π/2, sin⁻¹y+cos⁻¹y = π/2. Adding: (sin⁻¹x+sin⁻¹y)+(cos⁻¹x+cos⁻¹y) = π. So cos⁻¹x+cos⁻¹y = π − 2π/3 = π/3.
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