The trajectory of a water fountain jet at India Gate makes an angle tan⁻¹(4/3) with the horizontal. The sine of this angle is: A. 3/5 B. 4/5 C. 3/4 D. 4/3 Answer: B) 4/5 Explanation: If tan(θ) = 4/3, opp = 4, adj = 3, hyp = 5. Therefore, sin(θ) = 4/5.

imo class 12 inverse trigonometric functions

The trajectory of a water fountain jet at India Gate makes an angle tan⁻¹(4/3) with the horizontal. The sine of this angle is:

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The trajectory of a water fountain jet at India Gate makes an angle tan⁻¹(4/3) with the horizontal. The sine of this angle is:

Answer: B) 4/5

Explanation: If tan(θ) = 4/3, opp = 4, adj = 3, hyp = 5. Therefore, sin(θ) = 4/5.