If A = [[2, −1], [−1, 2]], then A² − 4A + 3I is equal to:
If A = [[2, −1], [−1, 2]], then A² − 4A + 3I is equal to:
- A. 0
- B. I
- C. 2I
- D. 3I
Answer: A) 0
Explanation: A² = [[2, −1], [−1, 2]] × [[2, −1], [−1, 2]] = [[4+1, −2−2], [−2−2, 1+4]] = [[5, −4], [−4, 5]]. 4A = [[8, −4], [−4, 8]]. A² − 4A = [[−3, 0], [0, −3]] = −3I. Then A² − 4A + 3I = −3I + 3I = 0.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.