For any two matrices A and B of suitable orders, (AB)' is equal to:
For any two matrices A and B of suitable orders, (AB)' is equal to:
- A. A'B'
- B. B'A'
- C. AB
- D. BA
Answer: B) B'A'
Explanation: By the reversal law of transposes for matrix multiplication, the transpose of a product is the product of the transposes in reverse order: (AB)' = B'A'.
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