A random variable X has a probability distribution P(X=0)=k, P(X=1)=2k, P(X=2)=3k. The value of k is: A. 1/3 B. 1/6 C. 1/5 D. 1/2 Answer: B) 1/6 Explanation: The sum of all probabilities must be 1. k + 2k + 3k = 6k = 1. Therefore, k = 1/6.

imo class 12 probability

A random variable X has a probability distribution P(X=0)=k, P(X=1)=2k, P(X=2)=3k. The value of k is:

VAVidaara Admin Asked 6d ago 0 views 0 answers

A random variable X has a probability distribution P(X=0)=k, P(X=1)=2k, P(X=2)=3k. The value of k is:

Answer: B) 1/6

Explanation: The sum of all probabilities must be 1. k + 2k + 3k = 6k = 1. Therefore, k = 1/6.

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