Bag I has 3 Red and 4 Black balls; Bag II has 5 Red and 6 Black balls. A bag is chosen at random and a ball is drawn, which is Red. The probability it came from Bag I is:
Bag I has 3 Red and 4 Black balls; Bag II has 5 Red and 6 Black balls. A bag is chosen at random and a ball is drawn, which is Red. The probability it came from Bag I is:
- A. 33/68
- B. 35/68
- C. 3/7
- D. 5/11
Answer: A) 33/68
Explanation: By Bayes Theorem: P(Bag1|Red) = (1/2 × 3/7) / [(1/2 × 3/7) + (1/2 × 5/11)] = (3/7) / (3/7 + 5/11) = (33/77) / (68/77) = 33/68.
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