If a binomial distribution has a Mean of 4 and a Variance of 2, the number of trials n is: A. 4 B. 8 C. 6 D. 10 Answer: B) 8 Explanation: Mean = np = 4. Variance = npq = 2. Dividing them: (npq)/(np) = 2/4, so q = 1/2. Since p = 1−q, p = 1/2. Substituting into np = 4 gives n(1/2) = 4, so n = 8.

imo class 12 probability

If a binomial distribution has a Mean of 4 and a Variance of 2, the number of trials n is:

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If a binomial distribution has a Mean of 4 and a Variance of 2, the number of trials n is:

A. 4
B. 8
C. 6
D. 10

Answer: B) 8

Explanation: Mean = np = 4. Variance = npq = 2. Dividing them: (npq)/(np) = 2/4, so q = 1/2. Since p = 1−q, p = 1/2. Substituting into np = 4 gives n(1/2) = 4, so n = 8.

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