A random variable X has a mean of 5 and a variance of 4. The value of E(X²) is: A. 21 B. 29 C. 9 D. 25 Answer: B) 29 Explanation: Var(X) = E(X²) − [E(X)]². So, 4 = E(X²) − 5². Thus, 4 = E(X²) − 25, meaning E(X²) = 29.

imo class 12 probability

A random variable X has a mean of 5 and a variance of 4. The value of E(X²) is:

VAVidaara Admin Asked 6d ago 0 views 0 answers

A random variable X has a mean of 5 and a variance of 4. The value of E(X²) is:

Answer: B) 29

Explanation: Var(X) = E(X²) − [E(X)]². So, 4 = E(X²) − 5². Thus, 4 = E(X²) − 25, meaning E(X²) = 29.

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