If f(x) = 3x + 2, then f⁻¹(x) is:
If f(x) = 3x + 2, then f⁻¹(x) is:
- A. (x − 2)/3
- B. (x + 2)/3
- C. x/3 − 2
- D. 3x − 2
Answer: A) (x − 2)/3
Explanation: Let y = 3x + 2 → x = (y − 2)/3. So f⁻¹(x) = (x − 2)/3.
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