The normal vector to the plane 2x−3y+6z−5=0 is:
The normal vector to the plane 2x−3y+6z−5=0 is:
- A. (2,−3,6)
- B. (−5,2,−3)
- C. (2,3,6)
- D. (1,1,1)
Answer: A) (2,−3,6)
Explanation: Coefficients of x, y, z give the normal vector.
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