The Cartesian equation of the line through (1,2,3) parallel to vector (2,−1,4) is: A. (x−1)/2 = (y−2)/(−1) = (z−3)/4 B. (x+1)/2 = (y+2)/(−1) = (z+3)/4 C. x/2 = y/(−1) = z/4 D. (x−1)/4 = (y−2)/(−1) = (z−3)/2 Answer: A) (x−1)/2 = (y−2)/(−1) = (z−3)/4 Explanation: Using point-direction form, symmetric equation is (x−1)/2=(y−2)/(−1)=(z−3)/4.

imo class 12 three dimensional geometry

The Cartesian equation of the line through (1,2,3) parallel to vector (2,−1,4) is:

VAVidaara Admin Asked 8d ago 0 views 0 answers

The Cartesian equation of the line through (1,2,3) parallel to vector (2,−1,4) is:

Answer: A) (x−1)/2 = (y−2)/(−1) = (z−3)/4

Explanation: Using point-direction form, symmetric equation is (x−1)/2=(y−2)/(−1)=(z−3)/4.