Equation of the plane passing through (1, 1, −1) and perpendicular to the line x/1 = y/2 = z/3 is:

Equation of the plane passing through (1, 1, −1) and perpendicular to the line x/1 = y/2 = z/3 is:

• A. x + 2y + 3z = 0
• B. x + 2y + 3z = 6
• C. x + y − z = 3
• D. x + 2y + 3z = 1

Answer: A) x + 2y + 3z = 0

Explanation: The plane's normal is the direction of the line, so n = i + 2j + 3k. Equation is 1(x−1) + 2(y−1) + 3(z+1) = 0 → x − 1 + 2y − 2 + 3z + 3 = 0 → x + 2y + 3z = 0.