Distance of point (1,1,1) from plane x+y+z=0 is:
Distance of point (1,1,1) from plane x+y+z=0 is:
- A. √3
- B. 1/√3
- C. 3
- D. 0
Answer: A) √3
Explanation: Distance=|3|/√3=√3.
0 Answers
Log in to post your own answer or join the discussion.
Distance of point (1,1,1) from plane x+y+z=0 is:
Answer: A) √3
Explanation: Distance=|3|/√3=√3.
No comments yet — start the discussion.