Distance of origin from plane 2x+2y+z−3=0 is:
Distance of origin from plane 2x+2y+z−3=0 is:
- A. 1
- B. 3/2
- C. 2/3
- D. 3
Answer: A) 1
Explanation: Distance = |−3|/√(2² + 2² + 1²) = 3/3 = 1.
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Distance of origin from plane 2x+2y+z−3=0 is:
Answer: A) 1
Explanation: Distance = |−3|/√(2² + 2² + 1²) = 3/3 = 1.
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