Find the distance of the point (2, 3, 4) from the plane 3x − 6y + 2z + 11 = 0.
Find the distance of the point (2, 3, 4) from the plane 3x − 6y + 2z + 11 = 0.
- A. 1 unit
- B. 2 units
- C. 1/7 units
- D. 0 units
Answer: A) 1 unit
Explanation: Distance = |3(2) − 6(3) + 2(4) + 11| / √(3² + (−6)² + 2²) = |6 − 18 + 8 + 11| / √(9 + 36 + 4) = |7| / √49 = 7 / 7 = 1 unit.
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