Distance of point (2,1,1) from plane 2x−2y+z−3=0 is:
Distance of point (2,1,1) from plane 2x−2y+z−3=0 is:
- A. 0
- B. 1/3
- C. 2/3
- D. 1
Answer: A) 0
Explanation: |4−2+1−3|/√9=0. Distance=0.
0 Answers
Log in to post your own answer or join the discussion.
Distance of point (2,1,1) from plane 2x−2y+z−3=0 is:
Answer: A) 0
Explanation: |4−2+1−3|/√9=0. Distance=0.
No comments yet — start the discussion.