A line has the Cartesian equation (x−3)/2 = (y+1)/−3 = (z−2)/4. Find the coordinates of a general point on this line.
A line has the Cartesian equation (x−3)/2 = (y+1)/−3 = (z−2)/4. Find the coordinates of a general point on this line.
- A. (2λ+3, −3λ−1, 4λ+2)
- B. (3λ+2, −λ−3, 2λ+4)
- C. (2λ−3, −3λ+1, 4λ−2)
- D. (3λ−2, λ+3, 2λ−4)
Answer: A) (2λ+3, −3λ−1, 4λ+2)
Explanation: Let (x−3)/2 = (y+1)/−3 = (z−2)/4 = λ. Then x = 2λ + 3, y = −3λ − 1, z = 4λ + 2.
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