Find the intercepts cut off by the plane 2x + y − z = 5.
Find the intercepts cut off by the plane 2x + y − z = 5.
- A. 5/2, 5, −5
- B. 2, 1, −1
- C. 5, 5, −5
- D. 5/2, 1, 1
Answer: A) 5/2, 5, −5
Explanation: Dividing by 5, we get (2x)/5 + y/5 − z/5 = 1, which implies x/(5/2) + y/5 + z/(−5) = 1. Intercepts are 5/2, 5, −5.
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