The distance between planes x+y+z=2 and x+y+z=5 is:
The distance between planes x+y+z=2 and x+y+z=5 is:
- A. √3
- B. 3/√3
- C. 3√3
- D. 1
Answer: B) 3/√3
Explanation: Distance=|5−2|/√3=3/√3.
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The distance between planes x+y+z=2 and x+y+z=5 is:
Answer: B) 3/√3
Explanation: Distance=|5−2|/√3=3/√3.
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