The perpendicular distance from the origin to the plane passing through the points (1, 0, 0), (0, 2, 0) and (0, 0, 3) is:
The perpendicular distance from the origin to the plane passing through the points (1, 0, 0), (0, 2, 0) and (0, 0, 3) is:
- A. 6/7
- B. 7/6
- C. 1
- D. 36/49
Answer: A) 6/7
Explanation: Plane intercepts are 1, 2, 3. Equation is x/1 + y/2 + z/3 = 1, or 6x + 3y + 2z − 6 = 0. Distance from (0,0,0) is |−6| / √(36 + 9 + 4) = 6 / √49 = 6/7.
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