What is the angle between the planes 3x + 4y − 5z = 9 and 2x + 6y + 6z = 7?
What is the angle between the planes 3x + 4y − 5z = 9 and 2x + 6y + 6z = 7?
- A. cos⁻¹(0)
- B. 90°
- C. 45°
- D. Both A and B
Answer: D) Both A and B
Explanation: Normals: n₁ = (3, 4, −5), n₂ = (2, 6, 6). Dot product = 3(2) + 4(6) + (−5)(6) = 6 + 24 − 30 = 0. Planes are perpendicular (90° or cos⁻¹(0)).
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