Aarav pushes a heavy box applying a force F = 5î + 3ĵ + 2k̂ Newtons. The box undergoes a displacement of d = 2î − ĵ N meters. What is the total work done by Aarav?
Aarav pushes a heavy box applying a force F = 5î + 3ĵ + 2k̂ Newtons. The box undergoes a displacement of d = 2î − ĵ N meters. What is the total work done by Aarav?
- A. 7 Joules
- B. 10 Joules
- C. 5 Joules
- D. 13 Joules
Answer: A) 7 Joules
Explanation: Work Done W = F.d = (5)(2) + (3)(−1) + (2)(0) = 10 − 3 = 7 Joules.
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