An auto-rickshaw travels along a path given by the vector 3î + 4ĵ. The magnitude of its acceleration is 10 m/s² directed parallel to its path. The acceleration vector is:
An auto-rickshaw travels along a path given by the vector 3î + 4ĵ. The magnitude of its acceleration is 10 m/s² directed parallel to its path. The acceleration vector is:
- A. 6î + 8ĵ
- B. 30î + 40ĵ
- C. 10î + 10ĵ
- D. 10(3î + 4ĵ)
Answer: A) 6î + 8ĵ
Explanation: Unit vector along path = (3î + 4ĵ)/√(3²+4²) = (3î + 4ĵ)/5. Acceleration vector = Magnitude × Unit vector = 10 × (3î + 4ĵ)/5 = 2(3î + 4ĵ) = 6î + 8ĵ.
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