If a and b are unit vectors and θ is the angle between them, then |a − b| is equal to:
If a and b are unit vectors and θ is the angle between them, then |a − b| is equal to:
- A. 2sin(θ/2)
- B. 2cos(θ/2)
- C. sin(θ/2)
- D. cos(θ/2)
Answer: A) 2sin(θ/2)
Explanation: |a − b|² = |a|² + |b|² − 2a.b = 1 + 1 − 2cosθ = 2(1 − cosθ) = 2(2sin²(θ/2)) = 4sin²(θ/2). Taking the square root gives 2sin(θ/2).
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