Calculate the area of a parallelogram whose diagonals are 3î + ĵ − 2k̂ and î − 3ĵ + 4k̂.
Calculate the area of a parallelogram whose diagonals are 3î + ĵ − 2k̂ and î − 3ĵ + 4k̂.
- A. 5√3
- B. 10√3
- C. 15
- D. 20
Answer: A) 5√3
Explanation: Area = ½|d₁ × d₂|. d₁ × d₂ = î(4−6) − ĵ(12−(−2)) + k̂(−9−1) = −2î − 14ĵ − 10k̂. Magnitude = √(4 + 196 + 100) = √300 = 10√3. Area = ½(10√3) = 5√3.
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