Find the angle between the vectors a = î − 2ĵ + 3k̂ and b = 3î − 2ĵ + k̂.
Find the angle between the vectors a = î − 2ĵ + 3k̂ and b = 3î − 2ĵ + k̂.
- A. cos⁻¹(5/7)
- B. cos⁻¹(10/14)
- C. cos⁻¹(5/14)
- D. Both A and B
Answer: D) Both A and B
Explanation: a.b = 3 + 4 + 3 = 10. |a| = √(1+4+9) = √14. |b| = √(9+4+1) = √14. cos(θ) = (a.b) / (|a||b|) = 10 / 14 = 5/7. Thus, cos⁻¹(5/7) and cos⁻¹(10/14) are the same.
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