JEE physics

In a Wheatstone bridge, $P = 10\ \Omega$, $Q = 30\ \Omega$, $R = 15\ \Omega$. Find the value of $S$ for balance.

AAntoineMartin95 Asked 3mo ago 1,254 views 1 answer

In a Wheatstone bridge, $P = 10\ \Omega$, $Q = 30\ \Omega$, $R = 15\ \Omega$. Find the value of $S$ for balance.

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 3mo ago ▲ 35

At balance: $\dfrac{P}{Q} = \dfrac{R}{S}$

$$S = \frac{QR}{P} = \frac{30 \times 15}{10} = 45\ \Omega$$

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Discussion (3)

TS
Tip for others: you can verify the answer quickly by checking the units.
Tushar Saxena · 3mo ago
NA
Does this approach generalise to the JEE Advanced version of this question?
Nisha Agarwal · 3mo ago
VA
Great discussion here. If you want more practice on this concept, check the related questions in this category.
Vidaara Admin · Vidaara Team · 3mo ago
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