In a Wheatstone bridge, P = 10, Q = 30, R = 15 — JEE Physics
In a Wheatstone bridge, $P = 10\ \Omega$, $Q = 30\ \Omega$, $R = 15\ \Omega$. Find the value of $S$ for balance.
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2mo ago
▲ 35
At balance: $\dfrac{P}{Q} = \dfrac{R}{S}$
$$S = \frac{QR}{P} = \frac{30 \times 15}{10} = 45\ \Omega$$
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Discussion (3)
TS
Tip for others: you can verify the answer quickly by checking the units.
NA
Does this approach generalise to the JEE Advanced version of this question?
VA
Great discussion here. If you want more practice on this concept, check the related questions in this category.