In YDSE, the slits are 0.5 mm apart and screen is 1 m away — JEE Physics
In YDSE, the slits are 0.5 mm apart and screen is 1 m away. Wavelength $\lambda = 600$ nm. Find the fringe width.
1 Answer
VAVidaara Admin
✓ Vidaara Team
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· 18d ago
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$$\beta = \frac{\lambda D}{d} = \frac{600\times10^{-9} \times 1}{0.5\times10^{-3}} = \frac{600\times10^{-9}}{5\times10^{-4}} = 1.2 \times 10^{-3} m = 1.2 mm$$
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Discussion (2)
C
Underrated solution. The way you set it up makes it almost obvious.
K
Thanks a ton, I was stuck on this exact problem for an hour.