[JEE Advanced 1993] prove by induction that tan 1 13 tan 1 17 tan 1 1 n
Prove by induction that $\tan^{-1}\frac13+\tan^{-1}\frac17+\cdots+\tan^{-1}\frac1{n^2+n+1}=\tan^{-1}\frac n{n+2}$.
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Answer: Proved.
Each term $\tan^{-1}\frac1{n^2+n+1}=\tan^{-1}(n+1)-\tan^{-1}n$ telescopes; with $\tan^{-1}(n+1)-\tan^{-1}1=\tan^{-1}\frac n{n+2}$.
JEE Advanced 1993 · Binomial Theorem — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.