[JEE Main 2007] $S=\{1,\dots,12\}$ is partitioned into labelled sets $A,B,C$ of equal size $4$. The number of ways is
$S=\{1,\dots,12\}$ is partitioned into labelled sets $A,B,C$ of equal size $4$. The number of ways is
(a) $\frac{12!}{(4!)^3}$
(b) $\frac{12!}{(4!)^4}$
(c) $\frac{12!}{3!(4!)^3}$
(d) $\frac{12!}{3!(4!)^4}$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
▲ 0
Correct answer: (a) $\frac{12!}{(4!)^3}$
Distinct labelled groups of size $4$: multinomial $\frac{12!}{4!\,4!\,4!}=\frac{12!}{(4!)^3}$.
JEE Main 2007 · Permutations and Combinations — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.