[JEE Main 2011] s 1 ways to put 10 identical balls in 4 distinct boxes with none
S-1: ways to put $10$ identical balls in $4$ distinct boxes with none empty is $\binom93$. S-2: ways to choose any $3$ of $9$ places is $\binom93$.
(a) S-1 true, S-2 true; S-2 not explanation
(b) S-1 true, S-2 false
(c) S-1 false, S-2 true
(d) S-1 true, S-2 true; S-2 explains S-1
1 Answer
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· 2d ago
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Correct answer: (d) S-1 true, S-2 true; S-2 explains S-1
Placing $3$ dividers in the $9$ gaps between balls gives $\binom93$; both statements true and S-2 is the explanation.
JEE Main 2011 · Permutations and Combinations — verified solution by the Vidaara Team.
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