[JEE Advanced 1988] Solve $|x^2+4x+3|+2x+5=0$.
Solve $|x^2+4x+3|+2x+5=0$.
1 Answer
VAVidaara Admin
✓ Vidaara Team
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· 1mo ago
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Answer: $x=-4$ and $x=-1-\sqrt3$.
Where $x^2+4x+3\ge0$: $x^2+6x+8=0\Rightarrow x=-4$ (valid). Where $<0$: $x^2+2x-2=0\Rightarrow x=-1-\sqrt3$ (valid in $(-3,-1)$).
JEE Advanced 1988 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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