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[JEE Advanced 2011] source partly garbled let x 0 y 0 solve 2x ln 2 3y ln

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[Source partly garbled] Let $(x_0,y_0)$ solve $(2x)^{\ln2}=(3y)^{\ln3}$ and $3^{\ln x}=2^{\ln y}$. Then $x_0$ is

(a) $\frac16$
(b) $\frac13$
(c) $\frac12$
(d) $6$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Correct answer: (a) $\frac16$

Taking logarithms of both relations and solving the linear system gives $x_0=\frac16$ (with $y_0=\frac13$).

JEE Advanced 2011 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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