[Source partly garbled] Let (x₀,y₀) solve (2x)^ 2=(3y)^ 3 and 3^ln x=2^ln y. Then x₀ is (a) 16 (b) 13 (c) 12 (d) 6

Correct answer: (a) 16 Taking logarithms of both relations and solving the linear system gives x₀= 16 (with y₀= 13). JEE Advanced 2011 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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[JEE Advanced 2011] [Source partly garbled] Let $(x_0,y_0)$ solve $(2x)^{\ln2}=(3y)^{\ln3}$ and $3^{\ln x}=2^{\ln y}$. Then $x_0$ is

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[Source partly garbled] Let $(x_0,y_0)$ solve $(2x)^{\ln2}=(3y)^{\ln3}$ and $3^{\ln x}=2^{\ln y}$. Then $x_0$ is

(a) $\frac16$
(b) $\frac13$
(c) $\frac12$
(d) $6$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 0

Correct answer: (a) $\frac16$

Taking logarithms of both relations and solving the linear system gives $x_0=\frac16$ (with $y_0=\frac13$).

JEE Advanced 2011 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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