[JEE Main 2013] tan a 1 cot a cot a 1 tan a can be written as
$\dfrac{\tan A}{1-\cot A}+\dfrac{\cot A}{1-\tan A}$ can be written as
(a) $\sin A\cos A+1$
(b) $\sec A\operatorname{cosec}A+1$
(c) $\tan A+\cot A$
(d) $\sec A+\operatorname{cosec}A$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (b) $\sec A\operatorname{cosec}A+1$
The expression simplifies to $1+\tan A+\cot A=1+\frac{\sin^2A+\cos^2A}{\sin A\cos A}=1+\sec A\operatorname{cosec}A$.
JEE Main 2013 · Trigonometry — verified solution by the Vidaara Team.
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