[JEE Advanced 2003] the coefficient of r 24 in 1 r 2 12 1 r 12 1
The coefficient of $r^{24}$ in $(1+r^2)^{12}(1+r^{12})(1+r^{24})$ is
(a) $\binom{12}6+3$
(b) $\binom{12}6+1$
(c) $\binom{12}6$
(d) $\binom{12}6+2$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (d) $\binom{12}6+2$
Contributions: $(r^2)^{12}$, $r^{12}\cdot r^{12}$ giving $\binom{12}6$, and $1\cdot r^{24}$. Total $\binom{12}6+2$.
JEE Advanced 2003 · Binomial Theorem — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.