JEE physics

The displacement of a wave is $y = 0.01\sin(2\pi t - \pi x)$ m. Find the wavelength, frequency, and wave speed.

NNabinThapa70 Asked 2mo ago 1,487 views 1 answer

The displacement of a wave is $y = 0.01\sin(2\pi t - \pi x)$ m. Find the wavelength, frequency, and wave speed.

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2mo ago ▲ 39

Comparing with $y = A\sin(\omega t - kx)$:

$$\omega = 2\pi \Rightarrow f = 1 Hz$$

$$k = \pi \Rightarrow \lambda = \frac{2\pi}{k} = 2 m$$

$$v = f\lambda = 1 \times 2 = 2 m/s$$

Log in to post your own answer or join the discussion.

Discussion (4)

RJ
Brilliant explanation, the substitution step is what I kept missing.
Rahul Joshi · 2mo ago
A
Brilliant explanation, the substitution step is what I kept missing.
AayushaRai25 · 2mo ago
MT
Clean and to the point. Bookmarking this for revision.
Manish Tiwari · 2mo ago
C
I solved it a slightly different way and got the same answer, good sign.
ChloeLefevre13 · 2mo ago
← Back to all questions