[JEE Advanced 1982] the larger of 99 50 100 50 and 101 50 is
The larger of $99^{50}+100^{50}$ and $101^{50}$ is ____
1 Answer
VAVidaara Admin
✓ Vidaara Team
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· 2d ago
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Answer: $101^{50}$.
Writing $101=100+1$, $99=100-1$, the binomial expansion shows $101^{50}-100^{50}>100^{50}-99^{50}$, hence $101^{50}>99^{50}+100^{50}$.
JEE Advanced 1982 · Binomial Theorem — verified solution by the Vidaara Team.
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