JEE PYQ

[JEE Advanced 1980] the least value of 2 log 10 x log x 0 01 for x

VAVidaara Admin Asked 2d ago 0 views 1 answer
#PYQJEE#JEE#JEE Advanced#1980#max-min-values#Quadratic Equations and Inequations

The least value of $2\log_{10}x-\log_x(0.01)$, for $x>1$, is

(a) $10$
(b) $2$
(c) $-0.01$
(d) none of these

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Correct answer: (d) none of these

$\log_x(0.01)=-\frac2{\log_{10}x}$, so the expression $=2t+\frac2t$ with $t=\log_{10}x>0$, minimum $4$ — not listed.

JEE Advanced 1980 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

Log in to post your own answer or join the discussion.

Discussion (0)

No comments yet — start the discussion.

← Back to all questions