The least value of 2log₁₀x- (0.01), for x>1, is (a) 10 (b) 2 (c) -0.01 (d) none of these

Correct answer: (d) none of these (0.01)=- 2 log₁₀x, so the expression =2t+ 2t with t=log₁₀x>0, minimum 4 — not listed. JEE Advanced 1980 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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[JEE Advanced 1980] The least value of $2\log_{10}x-\log_x(0.01)$, for $x>1$, is

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The least value of $2\log_{10}x-\log_x(0.01)$, for $x>1$, is

(a) $10$
(b) $2$
(c) $-0.01$
(d) none of these

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 0

Correct answer: (d) none of these

$\log_x(0.01)=-\frac2{\log_{10}x}$, so the expression $=2t+\frac2t$ with $t=\log_{10}x>0$, minimum $4$ — not listed.

JEE Advanced 1980 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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