The number of solutions of tan x+sec x=2cos x in [0,2π) is (a) 2 (b) 3 (c) 0 (d) 1

Correct answer: (a) 2 2sin²x+sin x-1=0→sin x= 12 (root -1 rejected), giving x= 6, 5π 6 — two solutions. JEE Main 2002 · Trigonometry — verified solution by the Vidaara Team.

JEE PYQ

[JEE Main 2002] the number of solutions of tan x sec x 2 cos x in 0

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The number of solutions of $\tan x+\sec x=2\cos x$ in $[0,2\pi)$ is

(a) $2$
(b) $3$
(c) $0$
(d) $1$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Correct answer: (a) $2$

$2\sin^2x+\sin x-1=0\Rightarrow\sin x=\frac12$ (root $-1$ rejected), giving $x=\frac\pi6,\frac{5\pi}6$ — two solutions.

JEE Main 2002 · Trigonometry — verified solution by the Vidaara Team.

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