[JEE Main 2003] the number of ways 6 men and 5 women dine at a round table
The number of ways $6$ men and $5$ women dine at a round table with no two women together is
(a) $7!\times5!$
(b) $6!\times5!$
(c) $30!$
(d) $5!\times4!$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 3d ago
▲ 0
Correct answer: (b) $6!\times5!$
Men around the table: $(6-1)!=5!$; women in the $6$ gaps: $^6P_5=6!$. Total $5!\times6!=6!\times5!$.
JEE Main 2003 · Permutations and Combinations — verified solution by the Vidaara Team.
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