[JEE Advanced 1988] the number of ways to arrange six and four signs in a line with
The number of ways to arrange six $+$ and four $-$ signs in a line with no two $-$ together is ____
1 Answer
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· 3d ago
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Answer: $35$.
Six $+$ create $7$ gaps; choose $4$ for the $-$ signs: $\binom74=35$.
JEE Advanced 1988 · Permutations and Combinations — verified solution by the Vidaara Team.
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