[JEE Main 2002] The period of $\sin^2\theta$ is
The period of $\sin^2\theta$ is
(a) $\pi^2$
(b) $\pi$
(c) $2\pi$
(d) $\frac\pi2$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
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Correct answer: (b) $\pi$
$\sin^2\theta=\frac{1-\cos2\theta}2$, which has period $\pi$.
JEE Main 2002 · Trigonometry — verified solution by the Vidaara Team.
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