[JEE Main 2009] The remainder when $8^{2n}-(62)^{2n+1}$ is divided by $9$ is
The remainder when $8^{2n}-(62)^{2n+1}$ is divided by $9$ is
(a) $2$
(b) $7$
(c) $8$
(d) $0$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
▲ 0
Correct answer: (a) $2$
$8\equiv-1$ and $62\equiv-1\pmod9$, so $8^{2n}-62^{2n+1}\equiv1-(-1)=2$.
JEE Main 2009 · Binomial Theorem — verified solution by the Vidaara Team.
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